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how to integrate $f(x)=\frac{1}{\cos x}$ with $x\in\Bbb R$?
I have a problem in finding the integral $$\int_{ -\infty}^\infty\frac{dx}{\cos x}$$ I know that cosine is periodic with period $2\pi$, and I also know that if $\cos x$ was a continuous function, I’d be able to say that the integral is $2\int_0^{2\pi}\frac{dx}{\cos x}$, but since cosine is not continuous on all of its domain (or at least that is what I’ve been taught), how am I supposed to solve this integral?
A:
If the domain of $\cos$ is all of $\mathbb{R}$ (or $[-\pi, \pi]$), then the integral can be evaluated explicitly. The result is well-known and is equal to $\frac{1}{\sin x}$
If the domain of $\cos$ is not all of $\mathbb{R}$ then we can start with a rectangle.
If $-\pi \le x \le \pi$, then the integral over $[-\pi,
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